Un arbre de probas très artisanal
Les curseurs permettent de modifier l'aspect

$A$

$C$

$\frac{1}{3}$

$q$

$A$

$C$

$\frac{3}{4}$

$\ldots$

$A$

$C$

$\frac{9}{11}$

...

$B$

$p$

$B$

$\dots$

$A$

$C$

$B$

$B$

$p_B(A)$

$p_B(B)$

$p_B(C)$

0,25

Ω = Point(yAxis)
hb = 1 (slider from 0 to 5, step 0.1)
noeud1 = 3 (slider from 0 to 5, step 0.1)
A_1: (hb, noeud1)
A_2: (hb, (-y(A_1)))
f = Segment(Ω, A_1)
g = Segment(Ω, A_2)
noeud2 = 0.9 (slider from 0 to 5, step 0.1)
A_{11}: ((2 * hb), y(A_1) + noeud2)
A_{12}: ((2 * hb), y(A_1) - noeud2)
h = Segment(A_1, A_{11})
i = Segment(A_1, A_{12})
A_{21}: ((2 * hb), y(A_2) + noeud2)
A_{22}: ((2 * hb), y(A_2) - noeud2)
j = Segment(A_2, A_{21})
k = Segment(A_2, A_{22})
A_3: (hb, 0)
l = Segment(Ω, A_3)
A_{13}: ((2 * hb), (y(A_{11}) + y(A_{12})) / 2)
m = Segment(A_1, A_{13})
B_{21}: ((2 * hb), noeud2)
B_{22}: ((2 * hb), (-noeud2))
B_{23}: ((2 * hb), 0)
A_{23}: ((2 * hb), (y(A_{21}) + y(A_{22})) / 2)
n = Segment(A_3, B_{21})
p = Segment(A_3, B_{23})
q = Segment(A_3, B_{22})
r = Segment(A_2, A_{23})