Frédéric Léon -- MATHS -- E. Brontë

Solutions au problème du pélican

\(\begin{array}{cccccc} \mathrm{mois} & \mathrm{AP} & \mathrm{DP} & \mathrm{BP} & \mathrm{PC} & \mathrm{PB + PC} \\\hline 1 & \frac{144}{17} & \frac{9}{17} & \frac{16\cdot \sqrt{370}}{17} & \frac{\sqrt{370}}{17} & \sqrt{370} \\\hline 2 & 8 & 1 & 8\cdot \sqrt{5} & \sqrt{5} & 9\cdot \sqrt{5} \\\hline 3 & \frac{144}{19} & \frac{27}{19} & \frac{16\cdot \sqrt{442}}{19} & \frac{3\cdot \sqrt{442}}{19} & \sqrt{442} \\\hline 4 & \frac{36}{5} & \frac{9}{5} & \frac{4\cdot \sqrt{481}}{5} & \frac{\sqrt{481}}{5} & \sqrt{481} \\\hline 5 & \frac{48}{7} & \frac{15}{7} & \frac{16\cdot \sqrt{58}}{7} & \frac{5\cdot \sqrt{58}}{7} & 3\cdot \sqrt{58} \\\hline 6 & \frac{72}{11} & \frac{27}{11} & \frac{8\cdot \sqrt{565}}{11} & \frac{3\cdot \sqrt{565}}{11} & \sqrt{565} \\\hline 7 & \frac{144}{23} & \frac{63}{23} & \frac{16\cdot \sqrt{610}}{23} & \frac{7\cdot \sqrt{610}}{23} & \sqrt{610} \\\hline 8 & 6 & 3 & 2\cdot \sqrt{73} & \sqrt{73} & 3\cdot \sqrt{73} \\\hline 9 & \frac{144}{25} & \frac{81}{25} & \frac{16\cdot \sqrt{706}}{25} & \frac{9\cdot \sqrt{706}}{25} & \sqrt{706} \\\hline 10 & \frac{72}{13} & \frac{45}{13} & \frac{8\cdot \sqrt{757}}{13} & \frac{5\cdot \sqrt{757}}{13} & \sqrt{757} \\\hline 11 & \frac{16}{3} & \frac{11}{3} & \frac{16\cdot \sqrt{10}}{3} & \frac{11\cdot \sqrt{10}}{3} & 9\cdot \sqrt{10} \\\hline 12 & \frac{36}{7} & \frac{27}{7} & \frac{4\cdot \sqrt{865}}{7} & \frac{3\cdot \sqrt{865}}{7} & \sqrt{865}\\\hline \end{array}\)